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Beginning of The End has left a new comment on your post "NHỮNG HẰNG ĐẲNG THỨC ĐÁNG NHỚ":

cho x²=a²+b²+ab va a+b=c.CM:2 x⁴=a⁴+b⁴+c⁴
đầu tiên đưa về lũy thừa 4 các biểu thức đề cho:
* a+b=c
<=>a⁴+4a³b+6a²b²+4ab³+b⁴=c⁴
*x²=a²+b²+ab
<=>x²=a²+b²+ab
<=>x⁴=(a²+b²+ab)²
<=>x⁴= a⁴+b⁴+2a²b²+2a³b+2ab³+2a²b²
<=>2x⁴=2(a⁴+b⁴+3a²b²+2a³b+2ab³)
<=> 2x⁴= 2a⁴+2b⁴+6a²b²+4a³b+4ab³
<=>2x⁴= a⁴+b⁴+(a⁴+b⁴+6a²b²+4a³b+4ab³)
2x⁴= a⁴+b⁴+c⁴


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Posted by Beginning of The End to Học Để Thi at Oct 11, 2021, 9:40 AM

Beginning of The End has left a new comment on your post "NHỮNG HẰNG ĐẲNG THỨC ĐÁNG NHỚ":

(ax+b)(x²+cx+1)=x³-3x+2
<=>ax³+(b+ac)x²+(a+bc)x+b= x³-3x+2
Để 2 hàm đồng nhất thì:
* b=2
* a=1
*2+1.c=0 =>c=-2
*1+2c=-3 =>c=-2
Vậy các giá trị a,c,b đều thỏa mãn.
Kết luận: (a,b,c)=(1,2,-2)

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Posted by Beginning of The End to Học Để Thi at Oct 11, 2021, 9:20 AM

 
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